Question 1:
Fill in the blanks:
(a) 1 lakh = _______________ ten thousand
(b) 1 million = _______________ hundred thousand
(c) 1 crore = _______________ ten lakh
(d) 1 crore = _______________ million
(e) 1 million = _______________ lakh
(a) 10 

(b) 10 

(c) 10 

(d) 10 

(e) 10 

Place commas correctly and write the numerals:
(a)
(b)Nine crore five lakh
(c)Seven crore
(d)
(e)
(a)73,75,307
(b)9,05,00,041
(c)7,52,21,302
(d)58,423,202
(e)23,30,010
Insert commas suitable and write the names according to Indian system of numeration:
(a)87595762
(b)8546283
(c)99900046
(d)98432701
(a) 8,75,95,762
Eight crore
(b) 85,46,283
(c) 9,99,00,046
Nine crore
(d) 9,84,32,701
Nine crore
Insert commas suitable and write the names according to International system of numeration:
(a)78921092
(b)7452283
(c)99985102
(d)48049831
(a) 78,921,092
(b) 7,452,483
Seven million four hundred
(c) 99,985,102
(d) 48,049,831
Estimate each of the following using general rule:
(a)730 + 998
(b)796 – 314
(c)12,904 + 2,888
(d)28,292 – 21,496
(a) 730 round off to 700 998 round off to 1000 Estimated sum = 1700
(c) 12904 round off to 13000
2888 round off to 
3000 
Estimated sum = 
16000 
(b) 796 round off to 800 314 round off to 300 Estimated sum = 500
(d) 28292 round off to 
28000 
21496 round off to 
21000 
Estimated difference= 
7000 
Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(a)439 + 334 + 4317
(b)1,08,737 – 47,599
(c)8325 – 491
(d)4,89,348 – 48,365
(a) 439 round off to 
400 
334 round off to 
300 
4317 round off to 
4300 
Estimated sum = 
5000 
(c) 8325 round off to 
8300 
491 round off to 
500 
Estimated difference = 7800
(b) 108734 round off to 
108700 
47599 round off to 
47600 
Estimated difference = 
61100 
(d) 489348 round off to 
489300 
48365 round off to 
48400 
Estimated difference = 
440900 
Estimate the following products using general rule:
(a)578 x 161
(b)5281 x 3491
(c)1291 x 592
(d)9250 x 29
A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Number of tickets sold on first day 
= 
1,094 
Number of tickets sold on second day 
= 
1,812 
Number of tickets sold on third day 
= 
2,050 
Number of tickets sold on fourth day 
= + 2,751 

Total tickets sold 
= 
7,707 
Therefore, 7,707 tickets were sold on all the four days.
Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Runs to achieve 
= 
10,000 
Runs scored 
= – 6,980 

Runs required 
= 
3,020 
Therefore, he needs 3,020 more runs.
In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
Number of votes secured by successful candidates 
= 
5,77,500 
Number of votes secured by his nearest rival 
= – 3,48,700 

Margin between them 
= 
2,28,800 
Therefore, the successful candidate won by a margin of 2,28,800 votes.
Kirti Bookstore sold books worth ₹2,85,891 in the first week of June and books worth ₹4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Books sold in first week 
= 
2,85,891 
Books sold in second week 
= + 4,00,768 

Total books sold 
= 
6,86,659 
Since, 4,00,768,> 2,85,891 


Therefore sale of second week is greater than that of first week.
Books sold in second week 
= 
4,00,768 
Books sold in first week 
= – 2,85,891 

More books sold in second week 
= 
1,14,877 
Therefore, 1,14,877 more books were sold in second week.
Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Greatest 
= 
76432 
Smallest 
= – 23467 

Difference 
= 
52965 
Therefore the difference is 52965.
A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Number of screws manufactured in one day 
= 2,825 
Number of days in the month of January (31 days) = 2,825 x 31 = 87,575
Therefore, the machine produced 87,575 screws in the month of January.
A merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1,200 each. How much money will remain with her after the purchase?
Cost of one radio 
= ₹ 1200 

Cost of 40 radios = 1200 x 40 
= ₹ 48,000 

Now, 


Total money with merchant 
= 
₹ 78,592 
Money spent by her 
= – ₹ 48,000 

Money left with her 
= 
₹ 30,592 
Therefore, ₹ 30,592 will remain with her after the purchase.
A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?
Wrong answer = 7236 x 65 
Correct answer = 7236 x 56 
7236 
7236 
x 65 
x 56 
36180 
43416 
43416 x 
36180 x 
470340 
405216 
Difference in answers = 470340 – 405216 = 65,124
To stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?
Cloth required to stitch one shirt 
= 2 m 15 cm 



= 2 x 100 cm + 15 cm 



= 215 cm 

Length of cloth = 40 m = 40 x 100 cm = 4000 cm 

Number of shirts can be stitched 
= 4000 ÷ 215 



18 

215 

4000 


− 
215 

1850 



−1720 



130 

Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a can which cannot carry beyond 800 kg?
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g Number of boxes = 800000 ÷ 4500
4500 
177 
800000 
− 4500 35000 −31500 35000
−31500
3500
Therefore, 177 boxes can be loaded.
The distance between the school and the house of a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.
Distance between school and home Distance between home and school Total distance covered in one day
Distance covered in six days
=1.875 km
=+ 1.875 km
=3.750 km
=3.750 x 6 = 22.500 km
Therefore, 22 km 500 m distance covered in six days.
A vessel has 4 litres and 500 ml of curd. In how many glasses each of 25 ml capacity, can it be filled?
Capacity of curd in a vessel = 4 litres 500 ml = 4 x 1000 ml + 500 ml = 4500 ml Capacity of one glass = 25 ml
Number of glasses can be filled = 4500 ÷ 25
180
25 4500
−25
200
−200
0
Therefore, 180 glasses can be filled by curd.
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